As always, if you spot any errors, or broken/missing links, or have any feedback then please let me know. And good luck to everyone getting back to school (or, like me, starting a new school) this week.. Enjoy! #UKMathsChat #MathsToday
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Finding equations of cubics & quadratics: f(x)=a1x^n+a2x^n-1+...+a(n+1)x⁰ = building instruction for a1 n-dimensional cuboids (or parts if a1<1) with a2=sum of the orthogonal edges, a3=half the sum of 2d-surfaces, ... a(n+1)=volume f(x)=1x³+2x²-3x =1(x+0)(x+3)(x-1) inflection point (-a2/na1,f(-2/3))
![My screenshot reads: Calculus for Mathophobes A geometric[al] approach [Drawing of a tesseract] f(x)=x⁴ => 4x³ is the new x⁴ A tesseract has 8 borders; cubes. [drawing of a cube] f(x)=x³ => 3x² is the new x³ A cube has 6 borders,; squares. [Drawing of a square] f(x)=x² => 2x is the new x² A square has 4 borders; edgesf] [Drawing of an edge] f(x)=x => 1 is the new x An edge has 2 borders; points [Drawing of a point] f(x)=1 => 0 is the new 1 f(x)= contant => 0 is the new constant => f(x)=x^n => nx⁽^n-1⁾ is the new x^n One cube represents only a quarter of a tesseract's relevant boundaries; One square represents only a third of a cube's relevant boundaries, two edges only half of a square's relevant boundaries, one point only half of an edge's boundaries => f(x)=x^n => F(x)= x^n+1/n+1 ...Who is afraid of [greek epsilon]?](https://cdn.bsky.app/img/feed_thumbnail/plain/did:plc:omyr27fmzj3phbagch4sqyub/bafkreicm7m2ifjuwwqj3rpjrplh5treyda4gsfqg7sezil6fwo7dd5mnti@jpeg)
aug 31, 2025, 6:17 pm • 2 0 • view
Thank you very much! We love your resources at my school. Good luck in your new job.
aug 31, 2025, 2:09 pm • 4 0 • view
Good luck with your new school! They are very lucky to have you.
aug 31, 2025, 2:17 pm • 4 0 • view